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x=3x^2-15x-30
We move all terms to the left:
x-(3x^2-15x-30)=0
We get rid of parentheses
-3x^2+x+15x+30=0
We add all the numbers together, and all the variables
-3x^2+16x+30=0
a = -3; b = 16; c = +30;
Δ = b2-4ac
Δ = 162-4·(-3)·30
Δ = 616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{616}=\sqrt{4*154}=\sqrt{4}*\sqrt{154}=2\sqrt{154}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{154}}{2*-3}=\frac{-16-2\sqrt{154}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{154}}{2*-3}=\frac{-16+2\sqrt{154}}{-6} $
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